Work any 3 of the following 4 problems.
In these exercises,
Let
be a group homomorphism; since , we can think of as a 1-dimensional representation of .If
is any representation of , we can form a new representation . The underlying vector space for this representation is just , and the “new” action of an element on a vector is given by the ruleProve that if
is irreducible, then is also irreducible.Prove that if
denotes the character of , then the character of is given by ; in other words, the trace of the action of on is given byRecall that in class we saw that
has an irreducible representation of dimension 2 whose character is given byObserve that
and conclude that , where is the sign homomorphism.On the other hand,
has an irreducible representation of dimension 3 whose character is given by(I’m not asking you to confirm that
is irreducible, though it would be straightforward to check that ).Prove that
as -representations.(In particular,
has at least two irreducible representations of dimension 3.)
Let
be a representation of .For an irreducible representation
, consider the set of all invariant subspaces that are isomorphic to as -representations.Put
Prove that
is an invariant subspace, and show that is isomorphic to a direct sum as -representations.Prove that the quotient representation
has no invariant subspaces isomorphic to as -representations.If
is a complete set of non-isomorphic irreducible representations for , prove that is the internal direct sum
Let
be the character of a representation of . For prove that .Is it true for any arbitrary class function
that for every ? (Give a proof or a counterexample…)For a prime number
, let be the field with elements. Let be an -dimensional vector space over for some natural number , and let be a non-degenerate bilinear form on .(A common example would be to take
the field of order , and the trace pairing).Let us fix a non-trivial group homomorphism
(recall that is an additive group, while is multiplicative). Thus If you want an explicit choice, setFor a vector
, consider the mapping given by the ruleShow that
is a group homomorphism .Show that the assignment
is injective (one-to-one).(This assignment is a function
. In fact, it is a group homomorphism. Do you see why? How do you make into a group?)Show that any group homomorphism
has the form for some .Conclude that there are exactly
group homomorphisms .